Bidding: (W) 1♠ - 3♠ - 6♠     Opening lead : K♣

Trick 1		North > K♣
Declarer (W) ♠ - A 10 9 8 6 ♥ - A 10 5 ♦ - A K 3 ♣ - A 3	A♣ w		2♣	Dummy (E) ♠ - K Q J 7 3 ♥ - K J 3 ♦ - Q J 10 ♣ - 9 2
		7♣ South		Won = 1 Lost = 0

The contract is 6♠, so Declarer can afford to lose only one trick.
There are two possible losers, one in ♥s, the other one in ♣s.

Declarer can not discard a ♣ loser because the red suits are of equal (3-cards) length in both hands.
In the ♥ suit he can finesse the Q♥ in either direction. This will have only a 50% chance of success.   Is there a better way ?